Bobby, Paul, Julian and Wesley shared $180. Wesley received
14 of the total amount of money received by Bobby, Paul and Julian. Bobby received
35 of the total amount for Paul and Julian. Paul received
12 as much money as Julian. If Paul gave all his money to Wesley, how much did Wesley have more than Bobby in the end?
Bobby |
Paul |
Julian |
Wesley |
Total |
4x6 |
1x6 |
5x6 |
3x3 |
5x3 |
|
|
|
1x5 |
2x5 |
|
|
9 u |
5 u |
10 u |
6 u |
30 u |
The total amount that Paul and Julian have is repeated. Make the total amount of Paul and Julian the same. LCM of 3 and 5 is 15.
The total amount that Bobby, Paul and Julian have is repeated. Make the total amount of Bobby, Paul and Julian the same. LCM of 24 and 4 is 24.
Total amount that Bobby, Paul, Julian and Wesley shared = 30 u
30 u = 180
1 u = 180 ÷ 30 = 6
|
Bobby |
Paul |
Julian |
Wesley |
Before |
9 u |
5 u |
10 u |
6 u |
Change |
|
- 5 u |
|
+ 5 u |
After |
9 u |
0 u |
10 u |
11 u |
Amount that Wesley had if Paul gave him all his money
= 6 u + 5 u
= 11 u
Amount that Wesley had more than Bobby
= 11 u - 9 u
= 2 u
= 2 x 6
= $12
Answer(s): $12