Riordan, Bryan, Lee and Ethan shared $225. Ethan received
23 of the total amount of money received by Riordan, Bryan and Lee. Riordan received
14 of the total amount for Bryan and Lee. Bryan received
12 as much money as Lee. If Bryan gave all his money to Ethan, how much did Ethan have more than Riordan in the end?
Riordan |
Bryan |
Lee |
Ethan |
Total |
3x5 |
2x5 |
5x5 |
1x3 |
4x3 |
|
|
|
1x4 |
2x4 |
|
|
3 u |
4 u |
8 u |
10 u |
25 u |
The total amount that Bryan and Lee have is repeated. Make the total amount of Bryan and Lee the same. LCM of 3 and 4 is 12.
The total amount that Riordan, Bryan and Lee have is repeated. Make the total amount of Riordan, Bryan and Lee the same. LCM of 15 and 3 is 15.
Total amount that Riordan, Bryan, Lee and Ethan shared = 25 u
25 u = 225
1 u = 225 ÷ 25 = 9
|
Riordan |
Bryan |
Lee |
Ethan |
Before |
3 u |
4 u |
8 u |
10 u |
Change |
|
- 4 u |
|
+ 4 u |
After |
3 u |
0 u |
8 u |
14 u |
Amount that Ethan had if Bryan gave him all his money
= 10 u + 4 u
= 14 u
Amount that Ethan had more than Riordan
= 14 u - 3 u
= 11 u
= 11 x 9
= $99
Answer(s): $99