Michael, Caden, Howard and Brandon shared $684. Brandon received
45 of the total amount of money received by Michael, Caden and Howard. Michael received
13 of the total amount for Caden and Howard. Caden received
23 as much money as Howard. If Howard gave all his money to Brandon, how much did Brandon have more than Caden in the end?
Michael |
Caden |
Howard |
Brandon |
Total |
5x4 |
4x4 |
9x4 |
1x5 |
3x5 |
|
|
|
2x3 |
3x3 |
|
|
5 u |
6 u |
9 u |
16 u |
36 u |
The total amount that Caden and Howard have is repeated. Make the total amount of Caden and Howard the same. LCM of 5 and 3 is 15.
The total amount that Michael, Caden and Howard have is repeated. Make the total amount of Michael, Caden and Howard the same. LCM of 20 and 5 is 20.
Total amount that Michael, Caden, Howard and Brandon shared = 36 u
36 u = 684
1 u = 684 ÷ 36 = 19
|
Michael |
Caden |
Howard |
Brandon |
Before |
5 u |
6 u |
9 u |
16 u |
Change |
|
|
- 9 u |
+ 9 u |
After |
5 u |
6 u |
0 u |
25 u |
Amount that Brandon had if Howard gave him all his money
= 16 u + 9 u
= 25 u
Amount that Brandon had more than Caden
= 25 u - 6 u
= 19 u
= 19 x 19
= $361
Answer(s): $361