Tommy, Andy, Howard and Bobby shared $100. Bobby received
23 of the total amount of money received by Tommy, Andy and Howard. Tommy received
14 of the total amount for Andy and Howard. Andy received
12 as much money as Howard. If Howard gave all his money to Bobby, how much did Bobby have more than Andy in the end?
Tommy |
Andy |
Howard |
Bobby |
Total |
3x5 |
2x5 |
5x5 |
1x3 |
4x3 |
|
|
|
1x4 |
2x4 |
|
|
3 u |
4 u |
8 u |
10 u |
25 u |
The total amount that Andy and Howard have is repeated. Make the total amount of Andy and Howard the same. LCM of 3 and 4 is 12.
The total amount that Tommy, Andy and Howard have is repeated. Make the total amount of Tommy, Andy and Howard the same. LCM of 15 and 3 is 15.
Total amount that Tommy, Andy, Howard and Bobby shared = 25 u
25 u = 100
1 u = 100 ÷ 25 = 4
|
Tommy |
Andy |
Howard |
Bobby |
Before |
3 u |
4 u |
8 u |
10 u |
Change |
|
|
- 8 u |
+ 8 u |
After |
3 u |
4 u |
0 u |
18 u |
Amount that Bobby had if Howard gave him all his money
= 10 u + 8 u
= 18 u
Amount that Bobby had more than Andy
= 18 u - 4 u
= 14 u
= 14 x 4
= $56
Answer(s): $56