Dylan, Pierre, Tim and Simon shared $252. Simon received ¹₆ of the total amount of money received by Dylan, Pierre and Tim. Dylan received ⁴₅ of the total amount for Pierre and Tim. Pierre received ¹₃ as much money as Tim. If Pierre gave all his money to Simon, how much did Simon have more than Dylan in the end?

Dylan	Pierre	Tim	Simon	Total
6x6			1x6	7x6
4x4	5x4
	1x5	3x5
16 u	5 u	15 u	6 u	42 u

The total amount that Pierre and Tim have is repeated.  Make the total amount of Pierre and Tim the same.  LCM of 4 and 5 is 20.

The total amount that Dylan, Pierre and Tim have is repeated.  Make the total amount of Dylan, Pierre and Tim the same. LCM of 36 and 6 is 36.

Total amount that Dylan, Pierre, Tim and Simon shared = 42 u

42 u = 252

1 u = 252 ÷ 42 = 6

	Dylan	Pierre	Tim	Simon
Before	16 u	5 u	15 u	6 u
Change		- 5 u		+ 5 u
After	16 u	0 u	15 u	11 u

Amount that Simon had if Pierre gave him all his money
= 6 u + 5 u
= 11 u

Amount that Simon had more than Dylan
= 11 u - 16 u
= -5 u
= -5 x 6
= $-30

Answer(s): $-30