Reggie, Ian, Bobby and Brandon shared $112. Brandon received
25 of the total amount of money received by Reggie, Ian and Bobby. Reggie received
13 of the total amount for Ian and Bobby. Ian received
23 as much money as Bobby. If Bobby gave all his money to Brandon, how much did Brandon have more than Ian in the end?
Reggie |
Ian |
Bobby |
Brandon |
Total |
5x4 |
2x4 |
7x4 |
1x5 |
3x5 |
|
|
|
2x3 |
3x3 |
|
|
5 u |
6 u |
9 u |
8 u |
28 u |
The total amount that Ian and Bobby have is repeated. Make the total amount of Ian and Bobby the same. LCM of 5 and 3 is 15.
The total amount that Reggie, Ian and Bobby have is repeated. Make the total amount of Reggie, Ian and Bobby the same. LCM of 20 and 5 is 20.
Total amount that Reggie, Ian, Bobby and Brandon shared = 28 u
28 u = 112
1 u = 112 ÷ 28 = 4
|
Reggie |
Ian |
Bobby |
Brandon |
Before |
5 u |
6 u |
9 u |
8 u |
Change |
|
|
- 9 u |
+ 9 u |
After |
5 u |
6 u |
0 u |
17 u |
Amount that Brandon had if Bobby gave him all his money
= 8 u + 9 u
= 17 u
Amount that Brandon had more than Ian
= 17 u - 6 u
= 11 u
= 11 x 4
= $44
Answer(s): $44