Seth, Riordan, Jack and Ken shared $72. Ken received
15 of the total amount of money received by Seth, Riordan and Jack. Seth received
13 of the total amount for Riordan and Jack. Riordan received
23 as much money as Jack. If Jack gave all his money to Ken, how much did Ken have more than Riordan in the end?
Seth |
Riordan |
Jack |
Ken |
Total |
5x4 |
1x4 |
6x4 |
1x5 |
3x5 |
|
|
|
2x3 |
3x3 |
|
|
5 u |
6 u |
9 u |
4 u |
24 u |
The total amount that Riordan and Jack have is repeated. Make the total amount of Riordan and Jack the same. LCM of 5 and 3 is 15.
The total amount that Seth, Riordan and Jack have is repeated. Make the total amount of Seth, Riordan and Jack the same. LCM of 20 and 5 is 20.
Total amount that Seth, Riordan, Jack and Ken shared = 24 u
24 u = 72
1 u = 72 ÷ 24 = 3
|
Seth |
Riordan |
Jack |
Ken |
Before |
5 u |
6 u |
9 u |
4 u |
Change |
|
|
- 9 u |
+ 9 u |
After |
5 u |
6 u |
0 u |
13 u |
Amount that Ken had if Jack gave him all his money
= 4 u + 9 u
= 13 u
Amount that Ken had more than Riordan
= 13 u - 6 u
= 7 u
= 7 x 3
= $21
Answer(s): $21