Dylan, Sean, Paul and Jeremy shared $48. Jeremy received
15 of the total amount of money received by Dylan, Sean and Paul. Dylan received
13 of the total amount for Sean and Paul. Sean received
23 as much money as Paul. If Sean gave all his money to Jeremy, how much did Jeremy have more than Dylan in the end?
Dylan |
Sean |
Paul |
Jeremy |
Total |
5x4 |
1x4 |
6x4 |
1x5 |
3x5 |
|
|
|
2x3 |
3x3 |
|
|
5 u |
6 u |
9 u |
4 u |
24 u |
The total amount that Sean and Paul have is repeated. Make the total amount of Sean and Paul the same. LCM of 5 and 3 is 15.
The total amount that Dylan, Sean and Paul have is repeated. Make the total amount of Dylan, Sean and Paul the same. LCM of 20 and 5 is 20.
Total amount that Dylan, Sean, Paul and Jeremy shared = 24 u
24 u = 48
1 u = 48 ÷ 24 = 2
|
Dylan |
Sean |
Paul |
Jeremy |
Before |
5 u |
6 u |
9 u |
4 u |
Change |
|
- 6 u |
|
+ 6 u |
After |
5 u |
0 u |
9 u |
10 u |
Amount that Jeremy had if Sean gave him all his money
= 4 u + 6 u
= 10 u
Amount that Jeremy had more than Dylan
= 10 u - 5 u
= 5 u
= 5 x 2
= $10
Answer(s): $10