Julie, Gwen, Kylie and Diana received a sum of money. Julie received
38 of the total amount of money Gwen, Kylie and Diana received. Gwen received
15 of the total amount of money Kylie and Diana received. Kylie received
13 as much money as Diana. If Julie received $48 more than Kylie, find the total sum of money the 4 girls received.
Julie |
Gwen |
Kylie |
Diana |
Total |
3x3 |
8x3 |
|
|
1x4 |
5x4 |
|
|
|
1x5 |
3x5 |
|
9 u |
4 u |
5 u |
15 u |
33 u |
The total amount that Kylie and Diana have is repeated. Make the total amount that Kylie and Diana have the same. LCM of 4 and 5 is 20.
The total amount that Gwen, Kylie and Diana have is repeated. Make the total amount that Gwen, Kylie and Diana have the same. LCM of 6 and 8 is 24.
Amount that Julie had more than Kylie
= 9 u - 5 u
= 4 u
4 u = 48
1 u = 48 ÷ 4 = 12
Total sum of money that 4 girls received
= 9 u + 4 u + 5 u + 15 u
= 33 u
= 33 x 12
= $396
Answer(s): $396