Pamela, Kathy, Linda and Jaslyn received a sum of money. Pamela received
58 of the total amount of money Kathy, Linda and Jaslyn received. Kathy received
15 of the total amount of money Linda and Jaslyn received. Linda received
13 as much money as Jaslyn. If Pamela received $190 more than Linda, find the total sum of money the 4 girls received.
Pamela |
Kathy |
Linda |
Jaslyn |
Total |
5x3 |
8x3 |
|
|
1x4 |
5x4 |
|
|
|
1x5 |
3x5 |
|
15 u |
4 u |
5 u |
15 u |
39 u |
The total amount that Linda and Jaslyn have is repeated. Make the total amount that Linda and Jaslyn have the same. LCM of 4 and 5 is 20.
The total amount that Kathy, Linda and Jaslyn have is repeated. Make the total amount that Kathy, Linda and Jaslyn have the same. LCM of 6 and 8 is 24.
Amount that Pamela had more than Linda
= 15 u - 5 u
= 10 u
10 u = 190
1 u = 190 ÷ 10 = 19
Total sum of money that 4 girls received
= 15 u + 4 u + 5 u + 15 u
= 39 u
= 39 x 19
= $741
Answer(s): $741