Xuan, Abi, Joelle and Yen received a sum of money. Xuan received ⁵₈ of the total amount of money Abi, Joelle and Yen received. Abi received ¹₃ of the total amount of money Joelle and Yen received. Joelle received ¹₅ as much money as Yen. If Xuan received $56 more than Joelle, find the total sum of money the 4 girls received.

Xuan	Abi	Joelle	Yen	Total
5x1	8x1
	1x2	3x2
		1x1	5x1
5 u	2 u	1 u	5 u	13 u

The total amount that Joelle and Yen have is repeated.  Make the total amount that Joelle and Yen have the same.  LCM of 6 and 3 is 6.

The total amount that Abi, Joelle and Yen have is repeated.  Make the total amount that Abi, Joelle and Yen have the same. LCM of 4 and 8 is 8.

Amount that Xuan had more than Joelle
= 5 u - 1 u
= 4 u

4 u = 56

1 u = 56 ÷ 4 = 14

Total sum of money that 4 girls received
= 5 u + 2 u + 1 u + 5 u 
= 13 u
= 13 x 14
= $182

Answer(s): $182