Jaslyn, Marion, Tiffany and Julie received a sum of money. Jaslyn received
25 of the total amount of money Marion, Tiffany and Julie received. Marion received
14 of the total amount of money Tiffany and Julie received. Tiffany received
15 as much money as Julie. If Marion received $45 less than Jaslyn, find the total sum of money the 4 girls received.
Jaslyn |
Marion |
Tiffany |
Julie |
Total |
2x3 |
5x3 |
|
|
1x3 |
4x3 |
|
|
|
1x2 |
5x2 |
|
6 u |
3 u |
2 u |
10 u |
21 u |
The total amount that Tiffany and Julie have is repeated. Make the total amount that Tiffany and Julie have the same. LCM of 6 and 4 is 12.
The total amount that Marion, Tiffany and Julie have is repeated. Make the total amount that Marion, Tiffany and Julie have the same. LCM of 5 and 5 is 15.
Amount that Marion had less than Jaslyn
= 6 u - 3 u
= 3 u
3 u = 45
1 u = 45 ÷ 3 = 15
Total sum of money that 4 girls received
= 6 u + 3 u + 2 u + 10 u
= 21 u
= 21 x 15
= $315
Answer(s): $315