Kylie, Opal, Diana and Gem received a sum of money. Kylie received
38 of the total amount of money Opal, Diana and Gem received. Opal received
13 of the total amount of money Diana and Gem received. Diana received
15 as much money as Gem. If Kylie received $14 more than Diana, find the total sum of money the 4 girls received.
Kylie |
Opal |
Diana |
Gem |
Total |
3x1 |
8x1 |
|
|
1x2 |
3x2 |
|
|
|
1x1 |
5x1 |
|
3 u |
2 u |
1 u |
5 u |
11 u |
The total amount that Diana and Gem have is repeated. Make the total amount that Diana and Gem have the same. LCM of 6 and 3 is 6.
The total amount that Opal, Diana and Gem have is repeated. Make the total amount that Opal, Diana and Gem have the same. LCM of 4 and 8 is 8.
Amount that Kylie had more than Diana
= 3 u - 1 u
= 2 u
2 u = 14
1 u = 14 ÷ 2 = 7
Total sum of money that 4 girls received
= 3 u + 2 u + 1 u + 5 u
= 11 u
= 11 x 7
= $77
Answer(s): $77