Xylia, Jean, Barbara and Wendy received a sum of money. Xylia received ²₅ of the total amount of money Jean, Barbara and Wendy received. Jean received ¹₃ of the total amount of money Barbara and Wendy received. Barbara received ¹₄ as much money as Wendy. If Xylia received $55 more than Barbara, find the total sum of money the 4 girls received.

Xylia	Jean	Barbara	Wendy	Total
2x4	5x4
	1x5	3x5
		1x3	4x3
8 u	5 u	3 u	12 u	28 u

The total amount that Barbara and Wendy have is repeated.  Make the total amount that Barbara and Wendy have the same.  LCM of 5 and 3 is 15.

The total amount that Jean, Barbara and Wendy have is repeated.  Make the total amount that Jean, Barbara and Wendy have the same. LCM of 4 and 5 is 20.

Amount that Xylia had more than Barbara
= 8 u - 3 u
= 5 u

5 u = 55

1 u = 55 ÷ 5 = 11

Total sum of money that 4 girls received
= 8 u + 5 u + 3 u + 12 u 
= 28 u
= 28 x 11
= $308

Answer(s): $308