Xylia, Diana, Shannon and Kimberly received a sum of money. Xylia received ²₅ of the total amount of money Diana, Shannon and Kimberly received. Diana received ¹₂ of the total amount of money Shannon and Kimberly received. Shannon received ¹₄ as much money as Kimberly. If Xylia received $20 more than Shannon, find the total sum of money the 4 girls received.

Xylia	Diana	Shannon	Kimberly	Total
2x3	5x3
	1x5	2x5
		1x2	4x2
6 u	5 u	2 u	8 u	21 u

The total amount that Shannon and Kimberly have is repeated.  Make the total amount that Shannon and Kimberly have the same.  LCM of 5 and 2 is 10.

The total amount that Diana, Shannon and Kimberly have is repeated.  Make the total amount that Diana, Shannon and Kimberly have the same. LCM of 3 and 5 is 15.

Amount that Xylia had more than Shannon
= 6 u - 2 u
= 4 u

4 u = 20

1 u = 20 ÷ 4 = 5

Total sum of money that 4 girls received
= 6 u + 5 u + 2 u + 8 u 
= 21 u
= 21 x 5
= $105

Answer(s): $105