Eva, Betty, Nora and Hazel received a sum of money. Eva received
38 of the total amount of money Betty, Nora and Hazel received. Betty received
15 of the total amount of money Nora and Hazel received. Nora received
13 as much money as Hazel. If Eva received $52 more than Nora, find the total sum of money the 4 girls received.
Eva |
Betty |
Nora |
Hazel |
Total |
3x3 |
8x3 |
|
|
1x4 |
5x4 |
|
|
|
1x5 |
3x5 |
|
9 u |
4 u |
5 u |
15 u |
33 u |
The total amount that Nora and Hazel have is repeated. Make the total amount that Nora and Hazel have the same. LCM of 4 and 5 is 20.
The total amount that Betty, Nora and Hazel have is repeated. Make the total amount that Betty, Nora and Hazel have the same. LCM of 6 and 8 is 24.
Amount that Eva had more than Nora
= 9 u - 5 u
= 4 u
4 u = 52
1 u = 52 ÷ 4 = 13
Total sum of money that 4 girls received
= 9 u + 4 u + 5 u + 15 u
= 33 u
= 33 x 13
= $429
Answer(s): $429