Emma, Victoria, Nicole and Xylia received a sum of money. Emma received
58 of the total amount of money Victoria, Nicole and Xylia received. Victoria received
15 of the total amount of money Nicole and Xylia received. Nicole received
13 as much money as Xylia. If Emma received $130 more than Nicole, find the total sum of money the 4 girls received.
Emma |
Victoria |
Nicole |
Xylia |
Total |
5x3 |
8x3 |
|
|
1x4 |
5x4 |
|
|
|
1x5 |
3x5 |
|
15 u |
4 u |
5 u |
15 u |
39 u |
The total amount that Nicole and Xylia have is repeated. Make the total amount that Nicole and Xylia have the same. LCM of 4 and 5 is 20.
The total amount that Victoria, Nicole and Xylia have is repeated. Make the total amount that Victoria, Nicole and Xylia have the same. LCM of 6 and 8 is 24.
Amount that Emma had more than Nicole
= 15 u - 5 u
= 10 u
10 u = 130
1 u = 130 ÷ 10 = 13
Total sum of money that 4 girls received
= 15 u + 4 u + 5 u + 15 u
= 39 u
= 39 x 13
= $507
Answer(s): $507