Xylia, Erika, Gillian and Penelope received a sum of money. Xylia received
58 of the total amount of money Erika, Gillian and Penelope received. Erika received
15 of the total amount of money Gillian and Penelope received. Gillian received
13 as much money as Penelope. If Xylia received $110 more than Gillian, find the total sum of money the 4 girls received.
Xylia |
Erika |
Gillian |
Penelope |
Total |
5x3 |
8x3 |
|
|
1x4 |
5x4 |
|
|
|
1x5 |
3x5 |
|
15 u |
4 u |
5 u |
15 u |
39 u |
The total amount that Gillian and Penelope have is repeated. Make the total amount that Gillian and Penelope have the same. LCM of 4 and 5 is 20.
The total amount that Erika, Gillian and Penelope have is repeated. Make the total amount that Erika, Gillian and Penelope have the same. LCM of 6 and 8 is 24.
Amount that Xylia had more than Gillian
= 15 u - 5 u
= 10 u
10 u = 110
1 u = 110 ÷ 10 = 11
Total sum of money that 4 girls received
= 15 u + 4 u + 5 u + 15 u
= 39 u
= 39 x 11
= $429
Answer(s): $429