At a carnival, there were 5 times as many males as females.
415 of the males were boys and the rest were men.
13 of the females were girls and the rest were women. Given that there were 57 more boys than girls, how many children were there altogether?
| Males |
Females |
| 5x3 |
1x3 |
| Boys |
Men |
Girls |
Women |
| 4 u |
11 u |
1 u |
2 u |
The total number of females is repeated. Make the total number of females the same. LCM of 1 and 3 is 3.
The total number of males is repeated. Make the total number of males the same.
Number of more boys than girls
= 4 u - 1 u
= 3 u
3 u = 57
1 u = 57 ÷ 3 = 19
Total number of children
= 4 u + 1 u
= 5 u
= 5 x 19
= 95
Answer(s): 95
