¹₂ of the children in a school were boys and the rest were girls. ²₃ of the boys and ¹₆ of the girls took part in a school event. 80 children took part. How many more girls were needed to take part in the school event so that it would be equal to the same number of boys who took part in the event?

Boys		Girls
1x6 = 6 u		1x6 = 6 u
Took part	Did not take part	Took part	Did not take part
2x2	1x2	1x1	5x1
4 u	2 u	1 u	5 u

Since ¹₂ of the children in a school were boys and the rest were girls, the total number of boys and girls is the same.
The total number of boys is repeated and the total number of girls is repeated.

Make the total number of boys and the total number of girls the same since they are equal. LCM of 3 and 6 is 6.

Number of children who took part
= 4 u + 1 u
= 5 u

5 u = 80

1 u = 80 ÷ 5 = 16

Number of more girls that were needed to take part in the school event so that it would be equal to the same number of boys who took part in the event
= 4 u - 1 u
= 3 u
= 3 x 16
= 48

Answer(s): 48