Jenson and Bryan have some black pens and some gold pens. The number of gold pens Jenson has is equal to the number of black pens Bryan has.
15 of Jenson's pens are black and
13 of Bryan's pens are gold. There are a total of 40 black pens. Find the total number of pens they have.
| Jenson |
Bryan |
Total |
| Black |
Gold |
Black |
Gold |
|
| |
1x4 |
1x4 |
|
|
| 1x1 |
4x1 |
2x2 |
1x2 |
|
| 1 u |
4 u |
4 u |
2 u |
11 u |
The number of Jenson's gold pens and Bryan's black pens is the same.
The number of Jenson's gold pens is repeated. The number of Bryan's black pens is repeated. Make the number of Jenson's gold pens and Bryan's black pens the same. LCM of 4 and 5 is 4.
Number of black pens
= 1 u + 4 u
= 5 u
5 u = 40
1 u = 40 ÷ 5 = 8
Total number of pens
= 1 u + 4 u + 4 u + 2 u
= 11 u
= 11 x 8
= 88
Answer(s): 88
