Jack and Luke have some green markers and some yellow markers. The number of yellow markers Jack has is equal to the number of green markers Luke has.
23 of Jack's markers are green and
16 of Luke's markers are yellow. There are a total of 90 green markers. Find the total number of markers they have.
Jack |
Luke |
Total |
Green |
Yellow |
Green |
Yellow |
|
|
1x5 |
1x5 |
|
|
2x5 |
1x5 |
5x1 |
1x1 |
|
10 u |
5 u |
5 u |
1 u |
21 u |
The number of Jack's yellow markers and Luke's green markers is the same.
The number of Jack's yellow markers is repeated. The number of Luke's green markers is repeated. Make the number of Jack's yellow markers and Luke's green markers the same. LCM of 1 and 3 is 5.
Number of green markers
= 10 u + 5 u
= 15 u
15 u = 90
1 u = 90 ÷ 15 = 6
Total number of markers
= 10 u + 5 u + 5 u + 1 u
= 21 u
= 21 x 6
= 126
Answer(s): 126