Mark and Vincent have some yellow notebooks and some silver notebooks. The number of silver notebooks Mark has is equal to the number of yellow notebooks Vincent has.
14 of Mark's notebooks are yellow and
56 of Vincent's notebooks are silver. There are a total of 44 yellow notebooks. Find the total number of notebooks they have.
Mark |
Vincent |
Total |
Yellow |
Silver |
Yellow |
Silver |
|
|
1x3 |
1x3 |
|
|
1x1 |
3x1 |
1x3 |
5x3 |
|
1 u |
3 u |
3 u |
15 u |
22 u |
The number of Mark's silver notebooks and Vincent's yellow notebooks is the same.
The number of Mark's silver notebooks is repeated. The number of Vincent's yellow notebooks is repeated. Make the number of Mark's silver notebooks and Vincent's yellow notebooks the same. LCM of 3 and 4 is 3.
Number of yellow notebooks
= 1 u + 3 u
= 4 u
4 u = 44
1 u = 44 ÷ 4 = 11
Total number of notebooks
= 1 u + 3 u + 3 u + 15 u
= 22 u
= 22 x 11
= 242
Answer(s): 242