John and Michael have some green pencils and some red pencils. The number of red pencils John has is equal to the number of green pencils Michael has.
15 of John's pencils are green and
13 of Michael's pencils are red. There are a total of 50 green pencils. Find the total number of pencils they have.
| John |
Michael |
Total |
| Green |
Red |
Green |
Red |
|
| |
1x4 |
1x4 |
|
|
| 1x1 |
4x1 |
2x2 |
1x2 |
|
| 1 u |
4 u |
4 u |
2 u |
11 u |
The number of John's red pencils and Michael's green pencils is the same.
The number of John's red pencils is repeated. The number of Michael's green pencils is repeated. Make the number of John's red pencils and Michael's green pencils the same. LCM of 4 and 5 is 4.
Number of green pencils
= 1 u + 4 u
= 5 u
5 u = 50
1 u = 50 ÷ 5 = 10
Total number of pencils
= 1 u + 4 u + 4 u + 2 u
= 11 u
= 11 x 10
= 110
Answer(s): 110
