Riordan and Henry have some silver markers and some grey markers. The number of grey markers Riordan has is equal to the number of silver markers Henry has. ¹₃ of Riordan's markers are silver and ³₄ of Henry's markers are grey. There are a total of 12 silver markers. Find the total number of markers they have.

Riordan		Henry		Total
Silver	Grey	Silver	Grey
	1x2	1x2
1x1	2x1	1x2	3x2
1 u	2 u	2 u	6 u	11 u

The number of Riordan's grey markers and Henry's silver markers is the same.

The number of Riordan's grey markers is repeated. The number of Henry's silver markers is repeated.  Make the number of Riordan's grey markers and Henry's silver markers the same.  LCM of 2 and 3 is 2.

Number of silver markers
= 1 u + 2 u
= 3 u

3 u = 12

1 u = 12 ÷ 3 = 4

Total number of markers
= 1 u + 2 u + 2 u + 6 u
= 11 u
= 11 x 4
= 44

Answer(s): 44