Brandon and Ben have some yellow markers and some red markers. The number of red markers Brandon has is equal to the number of yellow markers Ben has.
14 of Brandon's markers are yellow and
56 of Ben's markers are red. There are a total of 32 yellow markers. Find the total number of markers they have.
Brandon |
Ben |
Total |
Yellow |
Red |
Yellow |
Red |
|
|
1x3 |
1x3 |
|
|
1x1 |
3x1 |
1x3 |
5x3 |
|
1 u |
3 u |
3 u |
15 u |
22 u |
The number of Brandon's red markers and Ben's yellow markers is the same.
The number of Brandon's red markers is repeated. The number of Ben's yellow markers is repeated. Make the number of Brandon's red markers and Ben's yellow markers the same. LCM of 3 and 4 is 3.
Number of yellow markers
= 1 u + 3 u
= 4 u
4 u = 32
1 u = 32 ÷ 4 = 8
Total number of markers
= 1 u + 3 u + 3 u + 15 u
= 22 u
= 22 x 8
= 176
Answer(s): 176