Luis and Oscar have some brown pencils and some yellow pencils. The number of yellow pencils Luis has is equal to the number of brown pencils Oscar has.
14 of Luis's pencils are brown and
56 of Oscar's pencils are yellow. There are a total of 36 brown pencils. Find the total number of pencils they have.
Luis |
Oscar |
Total |
Brown |
Yellow |
Brown |
Yellow |
|
|
1x3 |
1x3 |
|
|
1x1 |
3x1 |
1x3 |
5x3 |
|
1 u |
3 u |
3 u |
15 u |
22 u |
The number of Luis's yellow pencils and Oscar's brown pencils is the same.
The number of Luis's yellow pencils is repeated. The number of Oscar's brown pencils is repeated. Make the number of Luis's yellow pencils and Oscar's brown pencils the same. LCM of 3 and 4 is 3.
Number of brown pencils
= 1 u + 3 u
= 4 u
4 u = 36
1 u = 36 ÷ 4 = 9
Total number of pencils
= 1 u + 3 u + 3 u + 15 u
= 22 u
= 22 x 9
= 198
Answer(s): 198