Brandon and Henry have some blue pens and some red pens. The number of red pens Brandon has is equal to the number of blue pens Henry has.
14 of Brandon's pens are blue and
16 of Henry's pens are red. There are a total of 40 blue pens. Find the total number of pens they have.
| Brandon |
Henry |
Total |
| Blue |
Red |
Blue |
Red |
|
| |
1x15 |
1x15 |
|
|
| 1x5 |
3x5 |
5x3 |
1x3 |
|
| 5 u |
15 u |
15 u |
3 u |
38 u |
The number of Brandon's red pens and Henry's blue pens is the same.
The number of Brandon's red pens is repeated. The number of Henry's blue pens is repeated. Make the number of Brandon's red pens and Henry's blue pens the same. LCM of 3 and 4 is 15.
Number of blue pens
= 5 u + 15 u
= 20 u
20 u = 40
1 u = 40 ÷ 20 = 2
Total number of pens
= 5 u + 15 u + 15 u + 3 u
= 38 u
= 38 x 2
= 76
Answer(s): 76
