Andy and Flynn have some green markers and some red markers. The number of red markers Andy has is equal to the number of green markers Flynn has. ¹₃ of Andy's markers are green and ⁴₅ of Flynn's markers are red. There are a total of 36 green markers. Find the total number of markers they have.

Andy		Flynn		Total
Green	Red	Green	Red
	1x2	1x2
1x1	2x1	1x2	4x2
1 u	2 u	2 u	8 u	13 u

The number of Andy's red markers and Flynn's green markers is the same.

The number of Andy's red markers is repeated. The number of Flynn's green markers is repeated.  Make the number of Andy's red markers and Flynn's green markers the same.  LCM of 2 and 3 is 2.

Number of green markers
= 1 u + 2 u
= 3 u

3 u = 36

1 u = 36 ÷ 3 = 12

Total number of markers
= 1 u + 2 u + 2 u + 8 u
= 13 u
= 13 x 12
= 156

Answer(s): 156