Xavier and John have some purple markers and some green markers. The number of green markers Xavier has is equal to the number of purple markers John has. ³₄ of Xavier's markers are purple and ¹₆ of John's markers are green. There are a total of 160 purple markers. Find the total number of markers they have.

Xavier		John		Total
Purple	Green	Purple	Green
	1x5	1x5
3x5	1x5	5x1	1x1
15 u	5 u	5 u	1 u	26 u

The number of Xavier's green markers and John's purple markers is the same.

The number of Xavier's green markers is repeated. The number of John's purple markers is repeated.  Make the number of Xavier's green markers and John's purple markers the same.  LCM of 1 and 4 is 5.

Number of purple markers
= 15 u + 5 u
= 20 u

20 u = 160

1 u = 160 ÷ 20 = 8

Total number of markers
= 15 u + 5 u + 5 u + 1 u
= 26 u
= 26 x 8
= 208

Answer(s): 208