Wesley and Vaidev have some brown markers and some blue markers. The number of blue markers Wesley has is equal to the number of brown markers Vaidev has.
15 of Wesley's markers are brown and
13 of Vaidev's markers are blue. There are a total of 20 brown markers. Find the total number of markers they have.
Wesley |
Vaidev |
Total |
Brown |
Blue |
Brown |
Blue |
|
|
1x4 |
1x4 |
|
|
1x1 |
4x1 |
2x2 |
1x2 |
|
1 u |
4 u |
4 u |
2 u |
11 u |
The number of Wesley's blue markers and Vaidev's brown markers is the same.
The number of Wesley's blue markers is repeated. The number of Vaidev's brown markers is repeated. Make the number of Wesley's blue markers and Vaidev's brown markers the same. LCM of 4 and 5 is 4.
Number of brown markers
= 1 u + 4 u
= 5 u
5 u = 20
1 u = 20 ÷ 5 = 4
Total number of markers
= 1 u + 4 u + 4 u + 2 u
= 11 u
= 11 x 4
= 44
Answer(s): 44