Ahmad and Gabriel have some blue pens and some yellow pens. The number of yellow pens Ahmad has is equal to the number of blue pens Gabriel has.
15 of Ahmad's pens are blue and
45 of Gabriel's pens are yellow. There are a total of 60 blue pens. Find the total number of pens they have.
Ahmad |
Gabriel |
Total |
Blue |
Yellow |
Blue |
Yellow |
|
|
1x4 |
1x4 |
|
|
1x1 |
4x1 |
1x4 |
4x4 |
|
1 u |
4 u |
4 u |
16 u |
25 u |
The number of Ahmad's yellow pens and Gabriel's blue pens is the same.
The number of Ahmad's yellow pens is repeated. The number of Gabriel's blue pens is repeated. Make the number of Ahmad's yellow pens and Gabriel's blue pens the same. LCM of 4 and 5 is 4.
Number of blue pens
= 1 u + 4 u
= 5 u
5 u = 60
1 u = 60 ÷ 5 = 12
Total number of pens
= 1 u + 4 u + 4 u + 16 u
= 25 u
= 25 x 12
= 300
Answer(s): 300