Tim and Gabriel have some silver markers and some yellow markers. The number of yellow markers Tim has is equal to the number of silver markers Gabriel has.
15 of Tim's markers are silver and
23 of Gabriel's markers are yellow. There are a total of 50 silver markers. Find the total number of markers they have.
Tim |
Gabriel |
Total |
Silver |
Yellow |
Silver |
Yellow |
|
|
1x4 |
1x4 |
|
|
1x1 |
4x1 |
1x4 |
2x4 |
|
1 u |
4 u |
4 u |
8 u |
17 u |
The number of Tim's yellow markers and Gabriel's silver markers is the same.
The number of Tim's yellow markers is repeated. The number of Gabriel's silver markers is repeated. Make the number of Tim's yellow markers and Gabriel's silver markers the same. LCM of 4 and 5 is 4.
Number of silver markers
= 1 u + 4 u
= 5 u
5 u = 50
1 u = 50 ÷ 5 = 10
Total number of markers
= 1 u + 4 u + 4 u + 8 u
= 17 u
= 17 x 10
= 170
Answer(s): 170