Dylan and Paul have some yellow markers and some red markers. The number of red markers Dylan has is equal to the number of yellow markers Paul has.
15 of Dylan's markers are yellow and
34 of Paul's markers are red. There are a total of 45 yellow markers. Find the total number of markers they have.
Dylan |
Paul |
Total |
Yellow |
Red |
Yellow |
Red |
|
|
1x4 |
1x4 |
|
|
1x1 |
4x1 |
1x4 |
3x4 |
|
1 u |
4 u |
4 u |
12 u |
21 u |
The number of Dylan's red markers and Paul's yellow markers is the same.
The number of Dylan's red markers is repeated. The number of Paul's yellow markers is repeated. Make the number of Dylan's red markers and Paul's yellow markers the same. LCM of 4 and 5 is 4.
Number of yellow markers
= 1 u + 4 u
= 5 u
5 u = 45
1 u = 45 ÷ 5 = 9
Total number of markers
= 1 u + 4 u + 4 u + 12 u
= 21 u
= 21 x 9
= 189
Answer(s): 189