Cole and Pierre have some white markers and some grey markers. The number of grey markers Cole has is equal to the number of white markers Pierre has. ³₄ of Cole's markers are white and ¹₆ of Pierre's markers are grey. There are a total of 120 white markers. Find the total number of markers they have.

Cole		Pierre		Total
White	Grey	White	Grey
	1x5	1x5
3x5	1x5	5x1	1x1
15 u	5 u	5 u	1 u	26 u

The number of Cole's grey markers and Pierre's white markers is the same.

The number of Cole's grey markers is repeated. The number of Pierre's white markers is repeated.  Make the number of Cole's grey markers and Pierre's white markers the same.  LCM of 1 and 4 is 5.

Number of white markers
= 15 u + 5 u
= 20 u

20 u = 120

1 u = 120 ÷ 20 = 6

Total number of markers
= 15 u + 5 u + 5 u + 1 u
= 26 u
= 26 x 6
= 156

Answer(s): 156