Riordan and Carl have some brown pens and some yellow pens. The number of yellow pens Riordan has is equal to the number of brown pens Carl has.
13 of Riordan's pens are brown and
23 of Carl's pens are yellow. There are a total of 12 brown pens. Find the total number of pens they have.
Riordan |
Carl |
Total |
Brown |
Yellow |
Brown |
Yellow |
|
|
1x2 |
1x2 |
|
|
1x1 |
2x1 |
1x2 |
2x2 |
|
1 u |
2 u |
2 u |
4 u |
9 u |
The number of Riordan's yellow pens and Carl's brown pens is the same.
The number of Riordan's yellow pens is repeated. The number of Carl's brown pens is repeated. Make the number of Riordan's yellow pens and Carl's brown pens the same. LCM of 2 and 3 is 2.
Number of brown pens
= 1 u + 2 u
= 3 u
3 u = 12
1 u = 12 ÷ 3 = 4
Total number of pens
= 1 u + 2 u + 2 u + 4 u
= 9 u
= 9 x 4
= 36
Answer(s): 36