Bryan and Cody have some yellow markers and some green markers. The number of green markers Bryan has is equal to the number of yellow markers Cody has.
14 of Bryan's markers are yellow and
13 of Cody's markers are green. There are a total of 64 yellow markers. Find the total number of markers they have.
Bryan |
Cody |
Total |
Yellow |
Green |
Yellow |
Green |
|
|
1x6 |
1x6 |
|
|
1x2 |
3x2 |
2x3 |
1x3 |
|
2 u |
6 u |
6 u |
3 u |
17 u |
The number of Bryan's green markers and Cody's yellow markers is the same.
The number of Bryan's green markers is repeated. The number of Cody's yellow markers is repeated. Make the number of Bryan's green markers and Cody's yellow markers the same. LCM of 3 and 4 is 6.
Number of yellow markers
= 2 u + 6 u
= 8 u
8 u = 64
1 u = 64 ÷ 8 = 8
Total number of markers
= 2 u + 6 u + 6 u + 3 u
= 17 u
= 17 x 8
= 136
Answer(s): 136