Container N and Container P were filled completely with chicken powder. The total mass of ¹₃ of the chicken powder in Container P and ¹₁₃ of the chicken powder in Container N was 590 g. If ³₁₃ of the chicken powder in Container N was poured out, the total mass of the chicken powder in both containers became 2.82 kg. How much chicken powder was in

1. Container N in grams?
2. Container P in grams?

(a)
Let the mass of the chicken powder in Container P be P.
Let the mass of the chicken powder in Container N be N.

¹₃ P + ¹₁₃ N = 590 --- (1)

Fraction of the chicken powder left in Container N after ³₁₃ of it was poured out
= 1 - ³₁₃
= ¹⁰₁₃

1 kg = 1000 g
2.82 kg = 2820 g

1 P + ¹⁰₁₃ N = 2820
1 P = 2820 - ¹⁰₁₃ N --- (2)

Make P the same.

(1)_x3
³₃ P + ³₁₃ N = 1770
1 P + ³₁₃ N = 1770
1 P = 1770 - ³₁₃ N --- (3)

(3) = (2) 
1770 - ³₁₃ N = 2820 - ¹⁰₁₃ X
¹⁰₁₃ N - ³₁₃ N = 2820 - 1770
⁷₁₃ N = 1050
¹₁₃ N = 1050 ÷ 7 = 150

¹³₁₃ N = 13 x 150 = 1950

1 N = 1950

Mass of Container N = 1950 g

(b)
From (1)
¹₃ P + 150 = 590
¹₃ P = 590 - 150 = 440

³₃ P = 3 x 440 = 1320

1 P = 1320

Mass of Container P = 1320 g

Answer(s): (a) 1950 g; (b) 1320 g