Container S and Container T were filled completely with flour. The total mass of ¹₄ of the flour in Container T and ¹₁₁ of the flour in Container S was 550 g. If ³₁₁ of the flour in Container S was poured out, the total mass of the flour in both containers became 2.8 kg. How much flour was in

1. Container S in grams?
2. Container T in grams?

(a)
Let the mass of the flour in Container T be T.
Let the mass of the flour in Container S be S.

¹₄ T + ¹₁₁ S = 550 --- (1)

Fraction of the flour left in Container S after ³₁₁ of it was poured out
= 1 - ³₁₁
= ⁸₁₁

1 kg = 1000 g
2.8 kg = 2800 g

1 T + ⁸₁₁ S = 2800
1 T = 2800 - ⁸₁₁ S --- (2)

Make T the same.

(1)_x4
⁴₄ T + ⁴₁₁ S = 2200
1 T + ⁴₁₁ S = 2200
1 T = 2200 - ⁴₁₁ S --- (3)

(3) = (2) 
2200 - ⁴₁₁ S = 2800 - ⁸₁₁ X
⁸₁₁ S - ⁴₁₁ S = 2800 - 2200
⁴₁₁ S = 600
¹₁₁ S = 600 ÷ 4 = 150

¹¹₁₁ S = 11 x 150 = 1650

1 S = 1650

Mass of Container S = 1650 g

(b)
From (1)
¹₄ T + 150 = 550
¹₄ T = 550 - 150 = 400

⁴₄ T = 4 x 400 = 1600

1 T = 1600

Mass of Container T = 1600 g

Answer(s): (a) 1650 g; (b) 1600 g