Container N and Container P were filled completely with rice flour. The total mass of ¹₄ of the rice flour in Container P and ¹₁₃ of the rice flour in Container N was 580 g. If ²₁₃ of the rice flour in Container N was poured out, the total mass of the rice flour in both containers became 3.72 kg. How much rice flour was in

1. Container N in grams?
2. Container P in grams?

(a)
Let the mass of the rice flour in Container P be P.
Let the mass of the rice flour in Container N be N.

¹₄ P + ¹₁₃ N = 580 --- (1)

Fraction of the rice flour left in Container N after ²₁₃ of it was poured out
= 1 - ²₁₃
= ¹¹₁₃

1 kg = 1000 g
3.72 kg = 3720 g

1 P + ¹¹₁₃ N = 3720
1 P = 3720 - ¹¹₁₃ N --- (2)

Make P the same.

(1)_x4
⁴₄ P + ⁴₁₃ N = 2320
1 P + ⁴₁₃ N = 2320
1 P = 2320 - ⁴₁₃ N --- (3)

(3) = (2) 
2320 - ⁴₁₃ N = 3720 - ¹¹₁₃ X
¹¹₁₃ N - ⁴₁₃ N = 3720 - 2320
⁷₁₃ N = 1400
¹₁₃ N = 1400 ÷ 7 = 200

¹³₁₃ N = 13 x 200 = 2600

1 N = 2600

Mass of Container N = 2600 g

(b)
From (1)
¹₄ P + 200 = 580
¹₄ P = 580 - 200 = 380

⁴₄ P = 4 x 380 = 1520

1 P = 1520

Mass of Container P = 1520 g

Answer(s): (a) 2600 g; (b) 1520 g