Container R and Container S were filled completely with chilli powder. The total mass of
15 of the chilli powder in Container S and
113 of the chilli powder in Container R was 470 g. If
213 of the chilli powder in Container R was poured out, the total mass of the chilli powder in both containers became 3.13 kg. How much chilli powder was in
- Container R in grams?
- Container S in grams?
(a)
Let the mass of the chilli powder in Container S be S.
Let the mass of the chilli powder in Container R be R.
15 S +
113 R = 470 --- (1)
Fraction of the chilli powder left in Container R after
213 of it was poured out
= 1 -
213 =
1113 1 kg = 1000 g
3.13 kg = 3130 g
1 S +
1113 R = 3130
1 S = 3130 -
1113 R --- (2)
Make S the same.
(1)
x5 55 S +
513 R = 2350
1 S +
513 R = 2350
1 S = 2350 -
513 R --- (3)
(3) = (2)
2350 -
513 R = 3130 -
1113 X
1113 R -
513 R = 3130 - 2350
613 R = 780
113 R = 780 ÷ 6 = 130
1313 R = 13 x 130 = 1690
1 R = 1690
Mass of Container R = 1690 g
(b)
From (1)
15 S + 130 = 470
15 S = 470 - 130 = 340
55 S = 5 x 340 = 1700
1 S = 1700
Mass of Container S = 1700 g
Answer(s): (a) 1690 g; (b) 1700 g