Container L and Container M were filled completely with pepper. The total mass of ¹₆ of the pepper in Container M and ¹₁₃ of the pepper in Container L was 620 g. If ⁴₁₃ of the pepper in Container L was poured out, the total mass of the pepper in both containers became 4.29 kg. How much pepper was in

1. Container L in grams?
2. Container M in grams?

(a)
Let the mass of the pepper in Container M be M.
Let the mass of the pepper in Container L be L.

¹₆ M + ¹₁₃ L = 620 --- (1)

Fraction of the pepper left in Container L after ⁴₁₃ of it was poured out
= 1 - ⁴₁₃
= ⁹₁₃

1 kg = 1000 g
4.29 kg = 4290 g

1 M + ⁹₁₃ L = 4290
1 M = 4290 - ⁹₁₃ L --- (2)

Make M the same.

(1)_x6
⁶₆ M + ⁶₁₃ L = 3720
1 M + ⁶₁₃ L = 3720
1 M = 3720 - ⁶₁₃ L --- (3)

(3) = (2) 
3720 - ⁶₁₃ L = 4290 - ⁹₁₃ X
⁹₁₃ L - ⁶₁₃ L = 4290 - 3720
³₁₃ L = 570
¹₁₃ L = 570 ÷ 3 = 190

¹³₁₃ L = 13 x 190 = 2470

1 L = 2470

Mass of Container L = 2470 g

(b)
From (1)
¹₆ M + 190 = 620
¹₆ M = 620 - 190 = 430

⁶₆ M = 6 x 430 = 2580

1 M = 2580

Mass of Container M = 2580 g

Answer(s): (a) 2470 g; (b) 2580 g