Container S and Container T were filled completely with curry powder. The total mass of ¹₃ of the curry powder in Container T and ¹₁₁ of the curry powder in Container S was 550 g. If ²₁₁ of the curry powder in Container S was poured out, the total mass of the curry powder in both containers became 2.85 kg. How much curry powder was in

1. Container S in grams?
2. Container T in grams?

(a)
Let the mass of the curry powder in Container T be T.
Let the mass of the curry powder in Container S be S.

¹₃ T + ¹₁₁ S = 550 --- (1)

Fraction of the curry powder left in Container S after ²₁₁ of it was poured out
= 1 - ²₁₁
= ⁹₁₁

1 kg = 1000 g
2.85 kg = 2850 g

1 T + ⁹₁₁ S = 2850
1 T = 2850 - ⁹₁₁ S --- (2)

Make T the same.

(1)_x3
³₃ T + ³₁₁ S = 1650
1 T + ³₁₁ S = 1650
1 T = 1650 - ³₁₁ S --- (3)

(3) = (2) 
1650 - ³₁₁ S = 2850 - ⁹₁₁ X
⁹₁₁ S - ³₁₁ S = 2850 - 1650
⁶₁₁ S = 1200
¹₁₁ S = 1200 ÷ 6 = 200

¹¹₁₁ S = 11 x 200 = 2200

1 S = 2200

Mass of Container S = 2200 g

(b)
From (1)
¹₃ T + 200 = 550
¹₃ T = 550 - 200 = 350

³₃ T = 3 x 350 = 1050

1 T = 1050

Mass of Container T = 1050 g

Answer(s): (a) 2200 g; (b) 1050 g