Container D and Container E were filled completely with chilli powder. The total mass of
13 of the chilli powder in Container E and
113 of the chilli powder in Container D was 440 g. If
313 of the chilli powder in Container D was poured out, the total mass of the chilli powder in both containers became 2.3 kg. How much chilli powder was in
- Container D in grams?
- Container E in grams?
(a)
Let the mass of the chilli powder in Container E be E.
Let the mass of the chilli powder in Container D be D.
13 E +
113 D = 440 --- (1)
Fraction of the chilli powder left in Container D after
313 of it was poured out
= 1 -
313 =
1013 1 kg = 1000 g
2.3 kg = 2300 g
1 E +
1013 D = 2300
1 E = 2300 -
1013 D --- (2)
Make E the same.
(1)
x3 33 E +
313 D = 1320
1 E +
313 D = 1320
1 E = 1320 -
313 D --- (3)
(3) = (2)
1320 -
313 D = 2300 -
1013 X
1013 D -
313 D = 2300 - 1320
713 D = 980
113 D = 980 ÷ 7 = 140
1313 D = 13 x 140 = 1820
1 D = 1820
Mass of Container D = 1820 g
(b)
From (1)
13 E + 140 = 440
13 E = 440 - 140 = 300
33 E = 3 x 300 = 900
1 E = 900
Mass of Container E = 900 g
Answer(s): (a) 1820 g; (b) 900 g