Container K and Container L were filled completely with flour. The total mass of
16 of the flour in Container L and
111 of the flour in Container K was 510 g. If
311 of the flour in Container K was poured out, the total mass of the flour in both containers became 3.38 kg. How much flour was in
- Container K in grams?
- Container L in grams?
(a)
Let the mass of the flour in Container L be L.
Let the mass of the flour in Container K be K.
16 L +
111 K = 510 --- (1)
Fraction of the flour left in Container K after
311 of it was poured out
= 1 -
311 =
811 1 kg = 1000 g
3.38 kg = 3380 g
1 L +
811 K = 3380
1 L = 3380 -
811 K --- (2)
Make L the same.
(1)
x6 66 L +
611 K = 3060
1 L +
611 K = 3060
1 L = 3060 -
611 K --- (3)
(3) = (2)
3060 -
611 K = 3380 -
811 X
811 K -
611 K = 3380 - 3060
211 K = 320
111 K = 320 ÷ 2 = 160
1111 K = 11 x 160 = 1760
1 K = 1760
Mass of Container K = 1760 g
(b)
From (1)
16 L + 160 = 510
16 L = 510 - 160 = 350
66 L = 6 x 350 = 2100
1 L = 2100
Mass of Container L = 2100 g
Answer(s): (a) 1760 g; (b) 2100 g