Container Y and Container Z were filled completely with flour. The total mass of
16 of the flour in Container Z and
113 of the flour in Container Y was 450 g. If
213 of the flour in Container Y was poured out, the total mass of the flour in both containers became 3.25 kg. How much flour was in
- Container Y in grams?
- Container Z in grams?
(a)
Let the mass of the flour in Container Z be Z.
Let the mass of the flour in Container Y be Y.
16 Z +
113 Y = 450 --- (1)
Fraction of the flour left in Container Y after
213 of it was poured out
= 1 -
213 =
1113 1 kg = 1000 g
3.25 kg = 3250 g
1 Z +
1113 Y = 3250
1 Z = 3250 -
1113 Y --- (2)
Make Z the same.
(1)
x6 66 Z +
613 Y = 2700
1 Z +
613 Y = 2700
1 Z = 2700 -
613 Y --- (3)
(3) = (2)
2700 -
613 Y = 3250 -
1113 X
1113 Y -
613 Y = 3250 - 2700
513 Y = 550
113 Y = 550 ÷ 5 = 110
1313 Y = 13 x 110 = 1430
1 Y = 1430
Mass of Container Y = 1430 g
(b)
From (1)
16 Z + 110 = 450
16 Z = 450 - 110 = 340
66 Z = 6 x 340 = 2040
1 Z = 2040
Mass of Container Z = 2040 g
Answer(s): (a) 1430 g; (b) 2040 g