Container Q and Container R were filled completely with chicken powder. The total mass of
16 of the chicken powder in Container R and
113 of the chicken powder in Container Q was 550 g. If
413 of the chicken powder in Container Q was poured out, the total mass of the chicken powder in both containers became 3.72 kg. How much chicken powder was in
- Container Q in grams?
- Container R in grams?
(a)
Let the mass of the chicken powder in Container R be R.
Let the mass of the chicken powder in Container Q be Q.
16 R +
113 Q = 550 --- (1)
Fraction of the chicken powder left in Container Q after
413 of it was poured out
= 1 -
413 =
913 1 kg = 1000 g
3.72 kg = 3720 g
1 R +
913 Q = 3720
1 R = 3720 -
913 Q --- (2)
Make R the same.
(1)
x6 66 R +
613 Q = 3300
1 R +
613 Q = 3300
1 R = 3300 -
613 Q --- (3)
(3) = (2)
3300 -
613 Q = 3720 -
913 X
913 Q -
613 Q = 3720 - 3300
313 Q = 420
113 Q = 420 ÷ 3 = 140
1313 Q = 13 x 140 = 1820
1 Q = 1820
Mass of Container Q = 1820 g
(b)
From (1)
16 R + 140 = 550
16 R = 550 - 140 = 410
66 R = 6 x 410 = 2460
1 R = 2460
Mass of Container R = 2460 g
Answer(s): (a) 1820 g; (b) 2460 g