Container L and Container M were filled completely with chicken powder. The total mass of ¹₇ of the chicken powder in Container M and ¹₁₃ of the chicken powder in Container L was 510 g. If ⁴₁₃ of the chicken powder in Container L was poured out, the total mass of the chicken powder in both containers became 3.87 kg. How much chicken powder was in

1. Container L in grams?
2. Container M in grams?

(a)
Let the mass of the chicken powder in Container M be M.
Let the mass of the chicken powder in Container L be L.

¹₇ M + ¹₁₃ L = 510 --- (1)

Fraction of the chicken powder left in Container L after ⁴₁₃ of it was poured out
= 1 - ⁴₁₃
= ⁹₁₃

1 kg = 1000 g
3.87 kg = 3870 g

1 M + ⁹₁₃ L = 3870
1 M = 3870 - ⁹₁₃ L --- (2)

Make M the same.

(1)_x7
⁷₇ M + ⁷₁₃ L = 3570
1 M + ⁷₁₃ L = 3570
1 M = 3570 - ⁷₁₃ L --- (3)

(3) = (2) 
3570 - ⁷₁₃ L = 3870 - ⁹₁₃ X
⁹₁₃ L - ⁷₁₃ L = 3870 - 3570
²₁₃ L = 300
¹₁₃ L = 300 ÷ 2 = 150

¹³₁₃ L = 13 x 150 = 1950

1 L = 1950

Mass of Container L = 1950 g

(b)
From (1)
¹₇ M + 150 = 510
¹₇ M = 510 - 150 = 360

⁷₇ M = 7 x 360 = 2520

1 M = 2520

Mass of Container M = 2520 g

Answer(s): (a) 1950 g; (b) 2520 g