Container L and Container M were filled completely with flour. The total mass of ¹₅ of the flour in Container M and ¹₁₁ of the flour in Container L was 620 g. If ⁴₁₁ of the flour in Container L was poured out, the total mass of the flour in both containers became 3.44 kg. How much flour was in

1. Container L in grams?
2. Container M in grams?

(a)
Let the mass of the flour in Container M be M.
Let the mass of the flour in Container L be L.

¹₅ M + ¹₁₁ L = 620 --- (1)

Fraction of the flour left in Container L after ⁴₁₁ of it was poured out
= 1 - ⁴₁₁
= ⁷₁₁

1 kg = 1000 g
3.44 kg = 3440 g

1 M + ⁷₁₁ L = 3440
1 M = 3440 - ⁷₁₁ L --- (2)

Make M the same.

(1)_x5
⁵₅ M + ⁵₁₁ L = 3100
1 M + ⁵₁₁ L = 3100
1 M = 3100 - ⁵₁₁ L --- (3)

(3) = (2) 
3100 - ⁵₁₁ L = 3440 - ⁷₁₁ X
⁷₁₁ L - ⁵₁₁ L = 3440 - 3100
²₁₁ L = 340
¹₁₁ L = 340 ÷ 2 = 170

¹¹₁₁ L = 11 x 170 = 1870

1 L = 1870

Mass of Container L = 1870 g

(b)
From (1)
¹₅ M + 170 = 620
¹₅ M = 620 - 170 = 450

⁵₅ M = 5 x 450 = 2250

1 M = 2250

Mass of Container M = 2250 g

Answer(s): (a) 1870 g; (b) 2250 g