Container V and Container W were filled completely with chicken powder. The total mass of
15 of the chicken powder in Container W and
113 of the chicken powder in Container V was 570 g. If
413 of the chicken powder in Container V was poured out, the total mass of the chicken powder in both containers became 3.49 kg. How much chicken powder was in
- Container V in grams?
- Container W in grams?
(a)
Let the mass of the chicken powder in Container W be W.
Let the mass of the chicken powder in Container V be V.
15 W +
113 V = 570 --- (1)
Fraction of the chicken powder left in Container V after
413 of it was poured out
= 1 -
413 =
913 1 kg = 1000 g
3.49 kg = 3490 g
1 W +
913 V = 3490
1 W = 3490 -
913 V --- (2)
Make W the same.
(1)
x5 55 W +
513 V = 2850
1 W +
513 V = 2850
1 W = 2850 -
513 V --- (3)
(3) = (2)
2850 -
513 V = 3490 -
913 X
913 V -
513 V = 3490 - 2850
413 V = 640
113 V = 640 ÷ 4 = 160
1313 V = 13 x 160 = 2080
1 V = 2080
Mass of Container V = 2080 g
(b)
From (1)
15 W + 160 = 570
15 W = 570 - 160 = 410
55 W = 5 x 410 = 2050
1 W = 2050
Mass of Container W = 2050 g
Answer(s): (a) 2080 g; (b) 2050 g